# How do you solve the compound inequalities 4p + 1 > −11 or 6p + 3 < 39?

Jul 30, 2018

$p > - 3$ or $p < 6$

#### Explanation:

In both instances, we want to isolate the variable. Let's start with our first inequality

$4 p + 1 > - 11$

Let's start by subtracting $1$ from both sides to get

$4 p > - 12$

Lastly, we divide both sides by $4$ to get

$p > - 3$

Now, let's tackle the second inequality

$6 p + 3 < 39$

Let's subtract $3$ from both sides to get

$6 p < 36$

Lastly, we can divide both sides by $6$ to get

$p < 6$

Therefore, the solutions of this inequality are

$p > - 3$ or $p < 6$

Hope this helps!