# How do you solve the compound inequality k+2>12 and k+2<=18?

Mar 2, 2017

$10 < k \le 16$

#### Explanation:

Isolate the variable $k$ by subtracting $2$ on both sides of the equation:
$k + 2 > 12$
$k + 2 - 2 > 12 - 2$
$k > 10$ or $10 < k$

$k + 2 \le 18$
$k + 2 - 2 \le 18 - 2$
$k \le 16$

In a combined statement: $10 < k \le 16$