How do you solve the differential equation given #f''(x)=x^(-3/2)#, f'(4)=2, f(0)=0?
Please see the explanation for steps leading to the equation:
Please remember the constant:
Evaluate at the given initial condition, 4:
Write f'(x) with the value of C:
The initial condition f(0) = 0 tells us that C = 0: