# How do you solve the equation 2x^2+16=x^2+7?

Jul 26, 2017

Not Real

#### Explanation:

1. Combine like terms:
$2 {x}^{2} + 16 = {x}^{2} + 7$
${x}^{2} = - 9$
2. Solve for x by taking the square root of both sides.
$\sqrt{{x}^{2}} = \pm \sqrt{- 9}$
The answer is not real, because you are taking the square root of a negative number. Nonetheless, the answer would be...
$x = \pm 3 i$