How do you solve the equation 2x^2-512=0?

1 Answer
Apr 28, 2017

x=+-16

Explanation:

Add 512 to both sides:

2x^2-512+512=0+512

This becomes:

2x^2=512

Divide both sides by 2:

(2x^2)/2=512/2

This becomes:

x^2=256

Square root both sides:

sqrt(x^2)=+-sqrt(256)

This becomes:

x=+-sqrt(256)

Break down 256 into its factors:

x=+-sqrt(2*2*2*2*2*2*2*2)

Take out pairs of the same number:

x=+-(2*2*2*2)

This leaves you with:

x=+-16