# How do you solve the equation -4(x^2-8)=16?

May 21, 2017

$x = + 2 \mathmr{and} x = - 2$

#### Explanation:

There is no $x$=term, so we can solve this by finding the square roots.

$- 4 \left({x}^{2} - 8\right) = 16 \text{ } \leftarrow \div - 4$

${x}^{2} - 8 = - 4 \text{ } \leftarrow$ add 8 to both sides

${x}^{2} = - 4 + 8$

${x}^{2} = 4$

$x = \pm \sqrt{4}$

$x = \pm 2$