How do you solve the equation log(x)+log(x-8)=log9?
1 Answer
Feb 9, 2018
Explanation:
Use
#log(x(x - 8)) = log9#
Therefore:
#x^2 - 8x = 9#
#x^2 - 8x - 9 = 0#
#(x- 9)(x + 1) = 0#
#x = 9 or -1#
But
Hopefully this helps!