How do you solve the following linear system: # - 12x + y = 15 , 3x + 2y = 3 #?

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Answer 1 · 2018-07-05T23:43:55

I got:
#x=-1#
#y=3#

Let us isolate #y# from the first equation and substitute into the second:

#y=12x+15#

so we get:

#3x+2(12x+15)=3#

solve for #x#:

#3x+24x+30=3#

#27x=-27#

#x=-27/27=-1#

and so:

#y=-12+15=3#