# How do you solve the following linear system: 14x + 3y = 12 , 14x - 3y = 0?

Apr 27, 2017

$\left(\setminus \frac{3}{7} , 2\right)$

#### Explanation:

Add $3 y$ to both sides of the second equation to get
$14 x = 3 y$

We can than plug in either of these values into the first equation to get
$3 y + 3 y = 12$

Solving we get
$6 y = 12$
$y = 2$

Plug this value of $y$ into either function to get the $x$ value.
$14 x - 3 \left(2\right) = 0$
$14 x - 6 = 0$
$14 x = 6$
$x = \setminus \frac{6}{14}$
$x = \setminus \frac{3}{7}$