Question

How do you solve the following linear system: `14x + 3y = 12 , 14x - 3y = 0`?

Answer 1

`(\frac{3}{7},2)`

Explanation:

Add `3y` to both sides of the second equation to get
`14x=3y`

We can than plug in either of these values into the first equation to get
`3y+3y=12`

Solving we get
`6y=12`
`y=2`

Plug this value of `y` into either function to get the `x` value.
`14x-3(2)=0`
`14x-6=0`
`14x=6`
`x=\frac{6}{14}`
`x=\frac{3}{7}`