# How do you solve the following linear system 2x - 6y = 2, 3x - 8y = 2 ?

Mar 18, 2018

see below

#### Explanation:

`We have, $2 x - 6 y = 2$ or $x = \left(2 + 6 y\right) / 2$ or $x = 1 + 3 y$.
The second equation is $3 x = 2 + 8 y$.
Substituting the value of $x$ in $2 n d$ equation,we get,
$3 \times \left(1 + 3 y\right) = 2 + 8 y$
Or, $3 + 9 y - 8 y - 2 = 0$
Or, $1 + y = 0$
Thus, $y = - 1$
Putting this value in the $1 s t$ equation, we get,
$x = 1 - 3$ or $x = - 2$