# How do you solve the following linear system: # –3x + 2y = 12 , 5x + 2y = -4 #?

##### 1 Answer

#### Explanation:

**1. The first step is to find similar coefficients between the two equations. Notice that both equations have a #2y# .**

**2. Because the coefficients are equal and not opposite, you have to times one of the equations by -1. For simplicity, lets use #-3x+ 2y =12#.**

**3. Now that the coefficients in front of #y# are opposite, we can add the two equations and the #y# values would cancel out.**

**4. Divide both side by #8# to get the value of #x#.**

**5. Substitute the value of #x# into one of the equations. For simplicity, lets use #5x+ 2y =-4# .**

**6. Simplify**

**7. Add 10 to both sides so that #2y# is alone.**

**8. Divide both side by #2# to get the value of #y#.**

**You now have found both the value of #x# and the value of #y#.**