How do you solve the following linear system: #3x-2y=3 , -x+y=1 #?

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Answer 1 · 2016-01-03T18:34:30

The solution for the system of equations is

#color(blue)(x=5,y=6#

#color(blue)(3x)-2y=3#.....equation #(1)#

#-x+y =1#, multiplying by #3#,
#-color(blue)(3x)+3y =3#.....equation #(2)#

Solving by elimination.

Subtracting equation #2# from #1#

#cancelcolor(blue)(3x)-2y=3#
#-cancelcolor(blue)(3x)+3y =3#

#color(blue)(y=6#

Finding #x# from equation #1#:
#3x-2y=3#

#3x=3+2y#

#3x=3+2xx6#

#3x=3+12#

#3x=15#

#x=15/3#

#color(blue)(x=5#