# How do you solve the following linear system: #4x+3y= -2 , 2x-2y= -8#?

##### 1 Answer

Nov 12, 2015

(x , y) = ( -2 , 2 )

#### Explanation:

Let the given equations be

4x + 3y = -2 ..........(i)

2x - 2y = -8 ...........(ii)

Lets multiply equation (ii) by 2, we get

4x - 4y = -16 ..........(iii)

Subtract equation (iii) from (i)

4x + 3y = -2

4x - 4y = -16

## ( - ) (+ ) (+)

```
0 + 7y = 14
y = 14/7 = 2
```

Substituting value of y in equation (i)

4x + 3 X 2 = -2

or, 4x = -2 -6 = -8

or, x = -8/4 = -2

Hence (x , y) = ( -2 , 2 )

Checking

4 X -2 + 3 X 2 = -2

or, -8 + 6 + -2

or -2 = -2

Hence LHS = RHS