How do you solve the following linear system #4x - 3y = -5 , 4x +- 4y = -4 #?

1 Answer
Aug 31, 2017

Answer:

I have started you off

Explanation:

#4x-3y=-5" "->" "y=4/3x +5/3" "..........Equation(1)#

#4x+4y=-4" "->" "y=-x-1" "............Equation(2)#

#4x-4y=-4" "->" "y=x+1" "................Equation(3)#
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Using #Equation(2)# substitute for #y# in #Equation(1)#

#y=-x-1" "->" "4/3x+5/3=-x-1#

#color(white)("dddddddddddd")->" "7/3x=- 8/3#

#color(white)("dddddddddddd")->" "x=-8/7#

Thus #y=-x-1" "->" "y=-(-8/7)-1 = +1/7#

So intersection of #Equation(1) and Equation(2) ->(x,y)=(-8/7,+1/7)#
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You repeat this approach for

#Eqn(2)->Eqn(3)#

Then for

#Eqn(1)->Eqn(3)#

I will let you do those.
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Tony B