# How do you solve the following linear system: #8x+3y-6z=4, x-2y-z=2, 4x+y-2z=-4 #?

##### 1 Answer

Combine

#### Explanation:

Given:

[1]

[2]

[3]

To eliminate

Multiply [2] by

#8#

[4]#color(white)("XXX")8x-16y-8z=16#

Subtract [4] from [1]

[5]#color(white)("XXX")19y+2z=-12# Multiply [3] by

#2#

[6]#color(white)("XXX")8x+2y-4z=-8#

Subtract [6] from [1]

[7]#color(white)("XXX")y-2z=12#

Now we have two equations in two unknowns:

[5]

[7]

Adding [5] and [7]

[8]

[9]

Substituting

[10]

[11]

Substituting

[12]

[13]