How do you solve the following linear system: # x + 6y = 28 , 3x + 2y = -5 #?

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Answer 1 · 2015-11-24T11:24:17

#x= -43/8#, #y=89/16#.

From the first equation, you know that

#x=28-6y#. Plugging this expression for #x# in the second equation gives

#3(28-6y)+2y=-5#

Expand:

#84 - 18y+2y=-5#

Isolate #y#:

#-16y = -89#

Solve for #y#: #y=89/16#.

Once #y# is known, you can deduce #x# from #x=28-6y#. So,

#x=28-6y = 28-6*89/16 = -43/8#