How do you solve the following linear system: y = 4x - 13 , y = 1/2x - 3/2 ?

Nov 14, 2015

$\left(\frac{23}{7} , \frac{1}{7}\right) \in m a t h \boldsymbol{Q \times Q}$

Explanation:

$y = 4 x - 13 = \frac{1}{2} x - \frac{3}{2}$ // times two

$2 y = 8 x - 26 = x - 3$

$8 x - x = - 3 + 26$

$x = \frac{23}{7}$

$y = 4 \cdot \frac{23}{7} - 13$