How do you solve the following system?: 1/3y = 3/4x + 5 , 3/2x - 8y = 2

1 Answer
Apr 1, 2018

x=-244/33 y=-18/11

Explanation:

(1/3)y=(3/4)x+5----(1)
(3/2)x-8y=2----(2)

Multiply (2) by (1/2)
(3/4)x-4y=1----(3)

Add(1)and(3), to makexdisappear
(1/3)y+(3/4)x-4y=(3/4)x+5+1
(3/4)x-(3/4)x+(1/3)y-4y=5+1
(-11/3)y=6
y=6*(-3/11)
y=-18/11

Substitudey=-18/11into(3)
(3/4)x-4(-18/11)=1
(3/4)x+72/11=1
(3/4)x=1-72/11
(3/4)x=-(61/11)
x=-(61/11)*(4/3)
x=-244/33

So, x=-244/33 y=-18/11