# How do you solve the following system: 11y + 3x = 4, x-2y=3 ?

Jul 17, 2017

$x = \frac{41}{17}$
$y = - \frac{5}{17}$

#### Explanation:

Let,
$3 x + 11 y = 4$ be eq 1
$x - 2 y = 3$ be eq 2

now, multiply eq 2 by -3 so as it will be cancelled out in the next step.
we get,
$- 3 x + 6 y = - 9$

$\Rightarrow 3 x + 11 y = 4$
$- 3 x + 6 y = - 9$

$\Rightarrow 17 y = - 5$
$\therefore y = - \frac{5}{17}$
now, substitute value of y in any equation,
u get $x = \frac{41}{17}$

ENJOY MATHS !!!!!

Jul 17, 2017

By arranging equation, $x = \frac{41}{17}$ and $y = - \frac{5}{17}$

#### Explanation:

$3 x + 11 y = 4$
$- 3 x + 6 y = - 9$ (when you enlarge the second equation with -3)
Combine these two equations and get
$17 y = - 5$

$y = - \frac{5}{17}$

Put this value in any original equation (for instance the first)

$3 x - \frac{55}{17} = 4$

$3 x = \frac{68 + 55}{17}$

$x = \frac{123}{51}$

$x = \frac{41}{17}$

This is your answer $x = \frac{41}{17}$ and $y = - \frac{5}{17}$