How do you solve the following system?: #15x +57y =62, 3x -y = -2#

1 Answer
Nov 16, 2015

Answer:

#(x,y)=(26/93,36/31)#

Explanation:

Given:
[1]#color(white)("XXX")15x+57y=62#
[2]#color(white)("XXX")3x-y=-2#

Multiply [2] by 5
[3]#color(white)("XXX")15x-5y=-10#

Subtract [3] from [1]
[4]#color(white)("XXX")62y=72#

Divide [4] by 62
[5]#color(white)("XXX")y=36/31#

Substitute #36/31# for #y# in [2]
[6]#color(white)("XXX")3x-36/31=-2#

Add #36/31# to both sides of [6]
[7]#color(white)("XXX")3x= -26/31#

Divide [7] by 3
[8]#color(white)("XXX")-26/93#