How do you solve the following system?: #-2x -8y =3, 3x -2y = -3#

1 Answer
Jun 1, 2016

Answer:

To substitute, we need to solve for one of the variables and then substitute this into the other equation.

Explanation:

#-2x = 3 + 8y#

#x = -3/2 - 4y#

#:. 3(-3/2 - 4y) - 2y = -3#

#-9/2 - 12y - 2y = -3#

#-14y = -3 + 9/2#

#-14y = 3/2#

#y = (3/2)/-14#

#y = -3/28#

Solving for x:

#3x - 2(-3/28) = -3#

#3x + 6/28 = -3#

#3x = -3 - 3/14#

#3x = -42/14 - 3/14#

#3x = -45/14#

#x = -45/42#

#x = -15/14#

Therefore, the solution set is #{-15/14, -3/28}#. Don't forget solutions always have to be presented in the form #{x, y}#.

Hopefully this helps!