Question

How do you solve the following system: # 3x – 5y = 53 , 2x + 5y= 2 #?

Answer 1

Solve by elimination:

`3x-5y=53`

`2x+5y=2`

We can eliminate `-5y` in the first equation by `5y` in the second equation
So,add both the equations:

`rarr(3x-5y=53)+(2x+5y=2)`

`rarr=5x=55`

`rarrx=55/5=11`

Substitute the value of `x` to the second equation:

`rarr2(11)-5y=2`

`rarr22+5y=2`

`rarr+5y=2-22`

`rarr+5y=-20`

`rarry=-20/5=-4`

So,`(x,y) =(11,-4)`