How do you solve the following system: #3x-y=12, 5x+2y=20 #?
We can start and find x by multiplying equation 1 by 2.
Now we can add both equations together and cancel the y' s.
Therefore, x = 4.
Now, we can back-substitute x to solve for y.
Our solution set is (4, 1) or x = 4 and y = 1