How do you solve the following system?: # -8x+3y=12 , -2x + 6y = -8 # Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer ali ergin Mar 15, 2016 #x=-16/7# #y=-44/21# Explanation: #color(red)(2)*(-8x+3y)=color(red)(2)*12# #-16x+color(blue)(6y)=24# #color(blue)(6y)=24+16x# #-2x+color(blue)(6y)=-8" "(1)# #-2x+24+16x=-8# #14x=-8-24# #14x=-32# #x=-32/14# #x=-16/7# #"use (1)"# #-2(-16/7)+6y=-8# #32/7+6y=-8# #6y=-8-32/7# #6y=(-56-32)/7# #y=-88/42# #y=-44/21# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1818 views around the world You can reuse this answer Creative Commons License