How do you solve the following system of equations?: -3x+y=6, 3x + 19y=19?

Dec 26, 2015

The solution is shown below using substitution method.

Explanation:

-3x + y = 6
y = 6 + 3x
3x + 19(6 + 3x) = 19
3x + 114 + 57x = 19
60x = -95
x = $- \frac{19}{12}$
-3($- \frac{19}{12}$) + y = 6
$\frac{19}{4}$ + y = 6
y = 6 - $\frac{19}{4}$
y = $\frac{5}{4}$

The solution set would be ($- \frac{19}{12}$, $\frac{5}{4}$)