# How do you solve the following system of equations?: -9x + 6y = 2 , 4x+y=8?

Mar 15, 2018

Solution: $x = \frac{46}{33} , y = \frac{80}{33}$

#### Explanation:

-9x+6y = 2 ; (1) , 4x+y=8 ; (2) . Multiplying equation(2)

by $6$ we get, 24x+6y=48 ; (3). Subtracting equation (1)

from equation(3) we get, $33 x = 46 \mathmr{and} x = \frac{46}{33}$. Putting

$x = \frac{46}{33}$ in equation (2) we get, $4 \cdot \frac{46}{33} + y = 8$ or

$\frac{184}{33} + y = 8 \mathmr{and} y = 8 - \frac{184}{33} \mathmr{and} y = \frac{264 - 184}{33}$ or

$y = \frac{80}{33}$. Solution: $x = \frac{46}{33} , y = \frac{80}{33}$ [Ans]