# How do you solve the following system of equations?: -x – 2y = 12 , 7x + 3y=10?

Sep 3, 2016

$x = \frac{56}{11}$ and $y = - \frac{94}{11}$

#### Explanation:

We can solve the system of equation by substitution method. First equation $- x - 2 y = 12$ gives us $x = - 2 y - 12$.

Substituting this in second equation $7 x + 3 y = 10$ gives us

7×(-2y-12)+3y=10 or

$- 14 y - 84 + 3 y = 10$ or

$- 11 y = 10 + 84 = 94$ or

$y = - \frac{94}{11}$

Hence, x=-2×(-94/11)-12

= $\frac{188}{11} - 12 = \frac{188 - 132}{11} = \frac{56}{11}$

Hence, $x = \frac{56}{11}$ and $y = - \frac{94}{11}$