How do you solve the inequality #-13+ 7y< 1#?

1 Answer
May 7, 2018

Answer:

#y<2#

Explanation:

You only need to isolate the variable: add #13# to both sides to get

#\cancel(-13) + 7y \cancel( + 13) < 1+13 \iff 7y < 14#

Now divide both sides by #7#. Note that, since #7# is positive, the inquality doesn't change from #<# to #>#:

#\frac{cancel(7)y}{cancel(7)} < \frac{cancel(14)2}{cancel(7)}#

and so the answer is #y<2#