Question

How do you solve the inequality `-13+ 7y< 1`?

Answer 1

`y<2`

Explanation:

You only need to isolate the variable: add `13` to both sides to get

`\cancel(-13) + 7y \cancel( + 13) < 1+13 \iff 7y < 14`

Now divide both sides by `7`. Note that, since `7` is positive, the inquality doesn't change from `<` to `>`:

`\frac{cancel(7)y}{cancel(7)} < \frac{cancel(14)2}{cancel(7)}`

and so the answer is `y<2`