# How do you solve the inequality 3a ≤ - 2 - 3a or  3a > 2 - a?

Apr 11, 2018

#### Explanation:

The first inequality can be solved by adding $3 a$ then dividing by $6$ :

$3 a \le - 2 - 3 a$

$6 a \le - 2$

$a \le - \frac{1}{3}$

The second inequality can be solved by adding $a$ then dividing
by $4$ :

$3 a > 2 - a$

$4 a > 2$

$a > \frac{1}{2}$

From these two inequalities we get:

$a \le - \frac{1}{3}$ , $\frac{1}{2} < a$