# How do you solve the inequality 4z >12 - z?

Feb 26, 2016

$z > \frac{12}{5}$

#### Explanation:

Collect terms in z to the left

add z to both sides of the inequality.

4z + z > 12 - z + z → 5z > 12

divide both sides by 5

$\cancel{5} \frac{z}{\cancel{5}} > \frac{12}{5} \Rightarrow z > \frac{12}{5}$