# How do you solve the inequality abs(x-3)<8?

Solution: $- 5 < x < 11$ . In interval notation : $\left(- 5 , 11\right)$
$| x - 3 | < 8 \mathmr{and} x - 3 < 8 \mathmr{and} x < 11$ OR
$| x - 3 | < 8 \mathmr{and} x - 3 > - 8 \mathmr{and} x > - 5$
Solution: $- 5 < x < 11$ . In interval notation: $\left(- 5 , 11\right)$ [Ans]