How do you solve the quadratic using the quadratic given 2n^2+6n-56?
You can solve this using factoring
x=4 and x=7 by dividing and factoring, factoring, or using the quadratic equation.
Method 1, divide and factor.
In this method, you try to get the x^2 term equal to 1x^2. This can be done in this expression by dividing by two because every term is evenly divisible by two. This gives you the expression
Your next step is to factor. You are looking for factors of -28 that add up to 3. In this case, it is -4 and 7. You can then set the next expression up. It is (x-4)(x+7) Assuming that you are solving for zero, you can use the zero products property, which says that anything times zero is zero. This means you can set the expression x-4=0 and x+7=0, yielding x=4 and x=-7.
Method 2, factor.
You are pretty much doing what is above, but without dividing by two first. Instead of looking for factors of-28 that add up to 3, you are looking for factors fo -112, or -56*2 that add up to 6. In this case, it is -8 and 14. The next step is to set the expression up. In this case, it is
Method 3, quadratic formula.
The quadratic formula lets you solve any quadratic equation, regardless of whether or not it can be factored. It is