Question

How do you solve the right triangle a=117 ft, b = 16.35 ft?

Answer 1

Assuming the most common labeling so that `c` is the hypotenuse

`c = sqrt(117^2 +16.35^2) " ft"`

`= 118.1369 " ft (approx.)"`

`sin(A) = 117/118.1369`
`rarr A = arcsin(117/118.1369) = 1.432 " radians"`

and similarly
`B= 0.1388 " radians"`