How do you solve the right triangle given A = 59°, a = 13, b = 14 ?

2 Answers
Jun 16, 2015

The given values are not those of a right triangle.

Explanation:

If #/_A = 59^@# and side #a# (the side opposite #/_A#) has a length of #13#

then the adjacent side has a length:
#color(white)("XXXX")##"cotan"(59^@)*13 = 7.811#
and the hypotenuse has a length:
#color(white)("XXXX")##"cosecant"(59^@)*13 = 15.166#

Neither of these matches the side given as #b=14#

Jun 16, 2015

Subtract angles A and C from #180^"o"# to find the missing angle B. Use the Pythagorean theorem to find side c, which is the hypotenuse. Angle B is #31^"o"# and the hypotenuse is 19.10#.

Explanation:

https://en.wikipedia.org/wiki/Right_triangle

Angles
The angles of any triangle add up to #180^"o"#. We know that angle C is #90^"o"# (the right angle), and the other angle A is #59^"o"#. So we can determine angle B by adding angles A and C together, and subtracting the result from #180^"o"#

Angle B: #180^"o"-(90^"o"+59^"o")=31^"o"#

Angle B = #31^"o"#

Sides
You have been given side a =13 and side b = 14, so you need to find side c, which is the hypotenuse. Use the Pythagorean theorem to do this.

#c^2=a^2+b^2# =

#c^2=13^2+14^2# =

#c^2=365#

#c=sqrt(365)=19.10#

#c="hypothenuse"=19.10#