# How do you solve the simultaneous equations 4x + 3y = 11 and 4x - 2y = 6?

Jul 20, 2015

$x = 2 , y = 1$

#### Explanation:

Subtract the second equation from the first and solve for $y$:
$\left(4 x + 3 y\right) - \left(4 x - 2 y\right) = 11 - 6$ => $5 y = 5$ => $y = 1$

Use this value in the first equation and solve for $x$:
$4 x + 3 y = 4 x + 3 = 11$ => $4 x = 8$ => $x = 2$

Jul 20, 2015

I found:
$x = 2$
$y = 1$

#### Explanation:

You can multiply the first equation by $- 1$ and then add the two equations (in columns) as:
{-4x-3y=-11
{4x-2y=6 add them:
$0 - 5 y = - 5$
$y = 1$
Substitute back into the first equation:
$4 x + 3 = 11$
$4 x = 8$
$x = 2$