# How do you solve the system #3x + 6y = 30# and #x + 6y = 20#?

##### 1 Answer

Apr 8, 2017

Solve by elimination to find:

#x=5" "# and#" "y=5/2#

#### Explanation:

Given:

#{ (3x+6y=30), (x+6y=20) :}#

To eliminate the term in

#2x=10#

and hence:

#x=5#

Substituting this value of

#5+6y=20#

Subtract

#6y=15#

Divide both sides by

#y = 15/6 = 5/2#