How do you solve the system #4x+4y+z=24#, #2x-4y+z=0#, and #5x-4y-5z=12#?
Add the equations to eliminate variables and solve.
Choose two equations that will easily cancel out.
The y's cancel out, leaving you with
Choose another two equations to get another binomial.
Again, the y's cancel out, leaving you with
Use substitution, making
You can then use this value in the equation
With these two values you can use any of the original equations to find the remaining value.
The final values are
This can be checked by plugging these values into the two remaining original equations.