# How do you solve the system #5x-10y=15# and #3x-2y=3# by multiplication?

##### 1 Answer

Jun 4, 2018

See explanation.

#### Explanation:

The system is:

#{(5x-10y=15),(3x-2y=3):}#

First we can see that all terms in the first equation are divisible by

#{(x-2y=3),(3x-2y=3):}#

Now the coefficients of

#{(-x+2y=-3),(3x-2y=3):}#

Now if we add both sides of both equations we get an equation with one unknown only:

#2x=0#

#x=0#

Now we can substitute the calculated alue of

#3*0-2y=3#

#-2y=3#

#y=-3/2#

Now we can write the answer:

**The system has one solution:**