# How do you solve the system 6x + 2y = 10 and -6x - 2y = 12?

Mar 19, 2016

No solution. The lines are parallel

#### Explanation:

If we transform both equations into their slope-intercept form, we have

$\left[1\right] 6 x + 2 y = 10$

$\left[1\right] \implies y = - 3 x + 5$

$\left[2\right] - 6 x - 2 y = 12$
$\left[2\right] \implies y = - 3 x - 6$

Both lines have the same slope but with different $y$-intercept.
The lines are parallel and will never intersect