# How do you solve the system 9a+2b=10 and 9a-2b=10?

Jun 17, 2015

$a = \frac{10}{9}$
$b = 0$

#### Explanation:

I would add the two equation together as:
{9a+2b=10
{9a-2b=10
$- - - \equiv -$
$18 a + / = 20$

So that $a = \frac{20}{18} = \frac{10}{9}$ and using this value into the first equation:
$9 \cdot \frac{10}{9} + 2 b = 10$
$b = 0$