How do you solve the system by graphing #3x-2y=-18# and #-3x-y=0#?

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Answer 1 · 2016-02-24T15:17:58

The solution is:
#color(blue)(x=-2#
#color(blue)(y=6#

#color(blue)(3x)- 2y = -18#......equation #(1)#

#color(blue)(-3x) -y = 0#......equation #(2)#

Solving by elimination:
#cancelcolor(blue)(3x)- 2y = -18#
#cancelcolor(blue)(-3x) -y = 0#

#-3y = -18#

#y = (-18) /(-3) #

#y = 6 #

Finding #x# from equation #1#:
#3x- 2y = -18#

#3x- 2 xx 6 = -18#

#3x- 12 = -18#

#3x= -18 +12#

#3x= -6#

#x=-6/3#

#color(blue)(x=-2#