How do you solve the system of equations #10x-2y=-92# and #7x+4y=-59#?

1 Answer
Feb 5, 2017

#x=-9# and #y=1#

Explanation:

In the given equations

#10x-2y=-92# ...............................(1) and

#7x+4y=-59# ...............................(2),

we find that coefficients of #y# are opposite in sign and in equation (2) it is double in (1).

Hence we double the equation (1) and add it equation (2) to get

#2xx(10x-2y)+7x+4y=-2xx92-59#

or #20x-4y+7x+4y=-184-59=-243#

or #27x=-243# and

#x=-243/27=-9#

Putting this in (1), we get #10xx(-9)-2y=-92#

or #-90-2y=-92# i.e. #-2y=-92+90=-2# and #y=1#

Hence, solution is #x=-9# and #y=1#