How do you solve the system of equations #10x-7y=-1# and #-2x-7y=-25#?

1 Answer
Jul 20, 2017

See a solution process below:

Explanation:

Step 1) Subtract the second equation:

#" "10x - 7y = -1#
#-(-2x - 7y = -25)#

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#10x - 7y = -1#
# ""2x + 7y = 25#

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#12x + 0 = 24#

#12x = 24#

#(12x)/color(red)(12) = 24/color(red)(12)#

#(color(red)(cancel(color(black)(12)))x)/cancel(color(red)(12)) = 2#

#x = 2#

Step 2) Substitute #2# for #x# in either of the equations and solve for #y#:

#10x - 7y = -1# becomes:

#(10 xx 2) - 7y = -1#

#20 - 7y = -1#

#-color(red)(20) + 20 - 7y = -color(red)(20) - 1#

#0 - 7y = -21#

#-7y = -21#

#(-7y)/color(red)(-7) = (-21)/color(red)(-7)#

#(color(red)(cancel(color(black)(-7)))y)/cancel(color(red)(-7)) = 3#

#y = 3#

The Solution Is: #x = 2# and #y = 3# or #(2, 3)#