How do you solve the system of equations #12x + 3y = 0# and #-48x - 12y = 0#?

1 Answer
Jul 6, 2017

See a solution process below:

Explanation:

If we multiply both sides of the first equation by #color(red)(-4)# which will keep the equation balanced we get:

#color(red)(-4)(12x + 3y) = color(red)(-4) xx 0#

#(color(red)(-4) xx 12x) + (color(red)(-4) xx 3y) = 0#

#-48x + (-12y) = 0#

#-48x - 12y = 0#

This is the same as the second equation. Therefore, the two equations represent the same line which means there are infinite solutions to this problem. For every point #(x, y)# in the first equation it is equal for the second equation.