How do you solve the system of equations #20x - 20y = 62# and #- 5x + 5y = 3#?

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Answer 1 · 2017-05-12T04:45:24

No solution.

The two equations are #20x-20y=62# ...................(A)

and #-5x+5y=3# ...................(B)

Multiplying (B) by #-4#, we get

#20x-20y=-12# ...................(C)

Comparing (A) and (C), we find that there are two different values of #20x-20y#, which is just not possible.

Hence, we have no solution.

When such equations are solved graphically, they result in two parallel lines and hence no intersecting point or solution.

graph{(20x-20y-62)(5x-5y+3)=0 [-10, 10, -5, 5]}