How do you solve the system of equations #2x - 20y = 0# and #3x - 10y = 20#?

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Answer 1 · 2018-01-14T03:59:35

#x=10#

#y=1#

#2x-20y=0# #(1)#

#3x-10y=20# #(2)#

#(1)#: #2x=20y#, #x=10y#

Plugging in #x=10y# for #(2)#, we get

#30y-10y=20#

#20y=20#

#y=1#

#:.x=10*1=10#

So the solutions are

#x=10#, #y=1#