How do you solve the system of equations #2x + 2y = 8# and #1x + 1y = 4#?

1 Answer
Aug 13, 2017

#y=4-x#

Refer to the explanation.

Explanation:

Solve the system of equations:

#"Equation 1":# #2x+2y=8#

#"Equation 2":# #x+y=4# (No coefficient is understood to be #1#.)

These are linear equations in standard form: #Ax+By=C#. They are solved simultaneously by substitution. The values for #x# and #y# represent the point of intersection between the lines on a graph.

I will start with #"Equation 2"# because it is simplest.

#y=4-x#

Substitute #4-x# for #y# in #"Equation 1"# and solve for #x#.

#2x+2(4-x)=8#

#2x+8-2x=8#

Subtract #8# from both sides.

#2x-2x=8-8#

#0=0#

There is an infinite number of solutions.

The only valid solution is the equation #y=4-x#. So there will be no point of intersection.

graph{y=4-x [-10, 10, -5, 5]}