How do you solve the system of equations $3x + 5y - 30 = 0$ and $x - y - 2 = 0$ ?

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Answer 1 · 2015-09-23T11:50:59

$x = 5$
$y=3$

$3x+5y−30=0$ ---------------(1)
$x−y−2=0$ -------------------(2)

Solve the equation (2) for $y$

$-y = 2-x$
$y = -2+x$

Substitute the value of $y = -2+x$ in equation (1)
$3x+5( -2+x)−30=0$

Simplify

$3x -10+5x −30=0$
$8x −40=0$
$8x =40$
$x=40/8=5$
$x = 5$

Substitute $x = 5$ in equation (2)

$5−y−2=0$

Simplify -
$3-y=0$
$-y =-3$
$y=3$

How do you solve the system of equations 3x + 5y - 30 = 03x + 5y - 30 = 0 and x - y - 2 = 0x - y - 2 = 0?