# How do you solve the system of equations 3x + 5y - 30 = 0 and x - y - 2 = 0?

Sep 23, 2015

$x = 5$
$y = 3$

#### Explanation:

3x+5y−30=0---------------(1)
x−y−2=0 -------------------(2)

Solve the equation (2) for $y$

$- y = 2 - x$
$y = - 2 + x$

Substitute the value of $y = - 2 + x$ in equation (1)
3x+5( -2+x)−30=0

Simplify

3x -10+5x −30=0
8x −40=0
$8 x = 40$
$x = \frac{40}{8} = 5$
$x = 5$

Substitute $x = 5$ in equation (2)

5−y−2=0

Simplify -
$3 - y = 0$
$- y = - 3$
$y = 3$