How do you solve the system of equations #4x + 12y = 8# and #3x-12y=6# by the addition method?

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Answer 1 · 2016-01-22T12:00:36

#x= 2# & #y = 0#

# 4x +12 y = 8# ------------------------------(1)
#3x - 12 y =6# ------------------------------(2)

Add (1) and (2) we get ,

#7x = 14#

#x= 14/7#

#x= 2 #

substitute in equation (1)

#4(2) + 12y = 8#

#8+12y = 8#

#12y = 0#

#y = 0#