How do you solve the system of equations #4x - 5y = 3# and #- 8x + 10y = - 6#?

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Answer 1 · 2016-12-04T15:53:15

Because -6 = -6 the solution set to this problem is all numbers.

Step 1) Solve the first equation for #x#:

#4x - 5y + 5y= 3 + 5y#

#4x = 3 + 5y#

#(4x)/4 = (3 + 5y)/4#

#x = (3 + 5y)/4#

Step 2) Substitute #(3 + 5y)/4# for #x# in the second equation and solve for #y#:

#-8((3 + 5y)/4) + 10y = -6#

#-2(3 + 5y) + 10y = -6#

#-6 - 10y + 10y = -6#

#-6 = -6#